public int reverse2(int x) { double ans=0; int flag=1; if(x<0){ flag=-1; } x=x*flag; while(x>0) { ans = 10 * ans + x % 10; x = x / 10; } if(ans>Integer.MAX_VALUE){//判断是否溢出 System.out.println(ans); return 0; } else return (int)(flag*ans); } 如上所示,因
Yukari's Birthday HDU4430 就是枚举+二分: 注意处理怎样判断溢出...(因为题目只要10^12) 先前还以为要用到快速幂和等比数列的快速求和(但肯定会超__int64) 而且这样判断会超时的... 还有题目中的And it's optional to place at most one candle at the center of the cake. (中间的蜡烛可有可无) 还有观察数据就知道:因为n最大10^12,r最多枚举到40,然后二分k的结果,看是否有符合条
Implement atoi to convert a string to an integer. Hint: Carefully consider all possible input cases. If you want a challenge, please do not see below and ask yourself what are the possible input cases. Notes: It is intended for this problem to be spe