福哥答案2020-04-23: 分批查询:分成500次count(),每次count()肯定小于等于2000条数据,经过测试,一次count()在.1ms左右,500次就是500ms.二分法(时间微超):count() 50万,25万,12.5万依次下去.rownum作差(时间超):rownum和id首个差值,取id.错位join(时间超):SELECT C_ID FROM t_vd20190814 WHERE C_ID NOT IN (SELECT C_ID+1 FROM t_vd201908
A - Poisonous Cookies 有毒还吃,有毒吧 #include <bits/stdc++.h> #define fi first #define se second #define pii pair<int,int> #define mp make_pair #define pb push_back #define space putchar(' ') #define enter putchar('\n') #define MAXN 100005 #define e