现有数据如上图所示,要求统计出日期相同的Count总数,并且加一列统计前面日期Count的总和 SELECT SUM([Count]) AS DayTotal, SUM(SUM([Count])) over (order by [Datetime]) Total, [datetime] FROM Table_3 GROUP BY [DateTime] ORDER BY [DateTime] DESC 结果如下: Total列是日期小于当前行的DayTotal列的总和:比如第三行 日期是2017-