题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=4772 题面: Zhuge Liang's Password Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 1404 Accepted Submission(s): 926 Problem Description In the anc
旋转一个数组以得到最大值. 陷阱就是:不能排序.须要模拟操作旋转,并设计公式计算旋转后的和. 要求是O(n)时间完毕. 原题: https://www.hackerrank.com/challenges/game-of-rotation #pragma once #include <stdio.h> class GameOfRotation { public: GameOfRotation() { int N = 0; scanf("%d", &N); int *A