<!-- 计算每两次消费的间隔天数 --> SELECT B.MEN_ID,TIMESTAMPDIFF(DAY,B.PRE_DATE,B.CURR_DATE) AS DAYS FROM ( <!-- 行变列 --> SELECT A.MEN_ID,A.ORDER_DATE AS CURR_DATE,@A.ORDER_DATE AS PRE_DATE,@A.ORDER_DATE:= A.ORDER_DATE FROM TBL_MAS_ORDER_MASTER A,(SELECT @A
CASE WHEN TIMESTAMPDIFF(MINUTE,o.createDate,o.chargingStartDate) != THEN 'APP解锁计费' ELSE '系统自动计费' END TIMESTAMPDIFF(MINUTE,o.createDate,o.chargingStartDate) o.chargingStartDate减去o.createDate相减后得到分钟,如果后者小于前者分钟为负数. SELECT TIMESTAMPDIFF(MONTH,'2009-10-01
先看一张表 create_time是订单创建时间,pay_time是支付时间 现在我想按照订单完成耗时的时间进行排序,并且取出来的数据中直接算好了差值,怎么用Sql呢,请看 select id,tid,payment_type,create_time,pay_time,(UNIX_TIMESTAMP(pay_time)-UNIX_TIMESTAMP(create_time))timeout from upay_order where pay_status=1 and create_time>'2
SELECT TIMESTAMPDIFF(MONTH,'2009-10-01','2009-09-01'); interval可是: SECOND 秒 SECONDS MINUTE 分钟 MINUTES HOUR 时间 HOURS DAY 天 DAYS MONTH 月 MONTHS YEAR 年 YEARS
javascript小数相减会出现一长串的小数位数的原因 <script> var a='38.8'; var b='6.8'; alert(parseFloat(a)-parseFloat(b)); var a=134.22; var b=6; alert(a*b); </script> 以上代码为什么产生一长串小数位出来,虽然比较精确,可没必要呀. 这个和数据结构有关系,整数型自动转换成正型计算,小数型直接转成double型计算.这是在内存中运算的时候必须这样,你该
info_rent = MysqlUtils.select_yezhu_rent() info_sale = MysqlUtils.select_yezhu_sale() now_time = datetime.datetime.now() #now time type is datetime and mysql spidertime is also datetime for i in info_rent: city = i[0] spidertime = i[1] d_time = now_t