Oracle数据库中字符串拼接的实现 select count() from THT_HTFKJL where ht=1: 假如结果为:31.例如上面例子想要给结果拼接字符串有二种实现方法,第一种使用’||’拼接,相当于’+’字符.select ‘第’||count()||’次付款’ from THT_HTFKJL where ht=1; 查询结果为:第3次付款2.使用concat函数进行字符串拼接,但是concat(char1,char2)只能拼接2个参数,如果想要多个字符串拼接需要内部再次使
方法一:listagg, 参考链接,从oracle11g后出现的新函数 如果拼接的字符串长度超过4000字节,会报ora-01489错误,ora-01489 字符串连接的结果过长 解决方案. SELECT id,count(name) as countname, LISTAGG(to_char(name), ',') WITHIN GROUP(ORDER BY name) AS pjname FROM ( select distinct B.id as id, B.name as name fr
首先看一下数据结构表 IF(OBJECT_ID('tempdb..#tProduct')IS NOT NULL) DROP TABLE #tProduct SELECT * INTO #tProduct FROM( AS ProductID,'aaa'AS ProductName UNION AS ProductID,'bbb'AS ProductName UNION AS ProductID,'ccc'AS ProductName UNION AS ProductID,'xxx'AS Prod
/* 分组之后拼接字符串 */ ;with t as( SELECT WorkflowId,Remark FROM dbo.OperatorAutomationProcess GROUP BY WorkflowId,Remark ) , H AS( SELECT WorkflowId, -- 分组的主键 STUFF( ( SELECT '_'+ Remark -- 要拼接的列 FROM t a WHERE b.WorkflowId = a.WorkflowId FOR XML PATH('')
备忘:这个函数最大是4000,根据拼接列的长度,通过限制拼接条数来防止拼接字符串过长错误 --这个情况是从子表中读取出具,这里直接把它当做查询字段处理,在子表中有所有数据 select info.id, (select wmsys.wm_concat(replace(st1.illegal, ',', ',')) from ts_acc_standards st1 group by st1.acc_id) as illegal_names form ts_info info where info
oracle中一个字符串包含另一个字符串中的所有字符 --解决监理报告中所勾选的标段信息,与该用户所管理的标段字符串不匹配的问题. select * from a where instr(a,b)>0;这个只能实现B字段是A字段中的某一部分的时候,如果想要不论顺序或者不相邻的字符时,定义函数可以实现 create or replace function checks(v_a varchar2,v_b varchar) return number as num number; cou
sqlserver2005前: --分组取最大最小常用sql--测试环境if OBJECT_ID('tb') is not null drop table tb;gocreate table tb( col1 int, col2 int, Fcount int)insert into tbselect 11,20,1 union allselect 11,22,1 union allselect 11,23,2 union allselect 11,24,5 union allselect 12