欢迎参加——BestCoder周年纪念赛(高质量题目+多重奖励) DNA Sorting Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 2182    Accepted Submission(s): 1062 Problem Description One measure of ``unsortedness'' in a sequenc

DNA Sorting Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 80832   Accepted: 32533 Description One measure of ``unsortedness'' in a sequence is the number of pairs of entries that are out of order with respect to each other. For instanc

[POJ1007]DNA Sorting 试题描述 One measure of ``unsortedness'' in a sequence is the number of pairs of entries that are out of order with respect to each other. For instance, in the letter sequence ``DAABEC'', this measure is 5, since D is greater than fo

DNA Sorting Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 88690 Accepted: 35644 Description One measure of unsortedness'' in a sequence is the number of pairs of entries that are out of order with respect to each other. For instance, in

点击打开链接 DNA Sorting Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 75164   Accepted: 30115 Description One measure of ``unsortedness'' in a sequence is the number of pairs of entries that are out of order with respect to each other. For

一. 题目 DNA Sorting Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 95052   Accepted: 38243 Description One measure of ``unsortedness'' in a sequence is the number of pairs of entries that are out of order with respect to each other. For i

DNA Sorting Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 95437   Accepted: 38399 Description One measure of ``unsortedness'' in a sequence is the number of pairs of entries that are out of order with respect to each other. For instanc

    DNA Sorting Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 77786   Accepted: 31201 Description One measure of ``unsortedness'' in a sequence is the number of pairs of entries that are out of order with respect to each other. For ins

DNA Sorting Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 2329    Accepted Submission(s): 1145 Problem Description One measure of ``unsortedness'' in a sequence is the number of pairs of entr

DNA Sorting Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 114211   Accepted: 45704 Description One measure of ``unsortedness'' in a sequence is the number of pairs of entries that are out of order with respect to each other. For instan

DNA Sorting Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 105159   Accepted: 42124 Description One measure of ``unsortedness'' in a sequence is the number of pairs of entries that are out of order with respect to each other. For instan

DNA Sorting Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 95209   Accepted: 38311 Description One measure of ``unsortedness'' in a sequence is the number of pairs of entries that are out of order with respect to each other. For instanc

这题比较简单,重点应该在如何减少循环次数. package practice; import java.io.BufferedInputStream; import java.util.Map; import java.util.Scanner; import java.util.TreeMap; /** * DNA sorting * * @author caiyu * @date 2014-11-5 */ public class POJ1007 { public static void m

Problem Description One measure of ``unsortedness'' in a sequence is the number of pairs of entries that are out of order with respect to each other. For instance, in the letter sequence ``DAABEC'', this measure is 5, since D is greater than four let

Description One measure of ``unsortedness'' in a sequence is the number of pairs of entries that are out of order with respect to each other. For instance, in the letter sequence ``DAABEC'', this measure is 5, since D is greater than four letters to

Description One measure of ``unsortedness'' in a sequence is the number of pairs of entries that are out of order with respect to each other. For instance, in the letter sequence ``DAABEC'', this measure is 5, since D is greater than four letters to

DNA排序 题目大意:给定多个ACGT序列,按照字母顺序算出逆序数,按逆序数从小到大排列 这题其实很简单,我们只要用一个归并排序算逆序数,然后快排就可以了(插入排序也可以,数据量不大),但是要注意的是他要保持原来的顺序,fcmop那里要写当a.inverse=b.inverse时,返回0 #include <iostream> #include <functional> #include <algorithm> using namespace std; typedef

http://poj.org/problem?id=1007 (题目链接) 题意 给出m个字符串,将其按照逆序对个数递增输出. Solution 树状数组经典应用. 代码 // poj1007 #include<algorithm> #include<iostream> #include<cstring> #include<cstdlib> #include<cstdio> #include<cmath> #include<st

题目链接:http://poj.org/problem?id=1007 本题属于字符串排序问题.思路很简单,把每行的字符串和该行字符串统计出的字母逆序的总和看成一个结构体.最后把全部行按照这个总和从小到大排序即可. #include <iostream> #include <algorithm> using namespace std; struct DNA { ]; int count; } d[]; int cmp(DNA a, DNA b) { return a.count

原题链接 题目大意:给定一串字符串,查找字符串里字母逆序排列的对数,按照由少到多的顺序把所有字符串进行排列. 解法:用C++字符串string类的iterator,从每个字符串的起始开始,查找逆序字符的个数,然后用qsort方法按照reverseCount的大小快速排序. 参考代码: #include<iostream> #include<string> #include<string.h> #include<cstdlib> #include<cst