直接上代码: def longestCommonPrefix(strs): """ :type strs: List[str] :rtype: str """ str_list = strs if len(str_list) > 1: s_last = str_list.pop() common_str = '' common = '' for num, str_ in enumerate(str_list): if num is 0: i
F - LCS Time Limit: 2 sec / Memory Limit: 1024 MB Score : 100100 points Problem Statement You are given strings ss and tt. Find one longest string that is a subsequence of both ss and tt. Notes A subsequence of a string xx is the string obtained by r
先要搞明白:最长公共子串和最长公共子序列的区别. 最长公共子串(Longest Common Substirng):连续 最长公共子序列(Longest Common Subsequence,LCS):不必连续 实在是汗颜,网上做一道题半天没进展: 给定一个字符串s,你可以从中删除一些字符,使得剩下的串是一个回文串.如何删除才能使得回文串最长呢?输出需要删除的字符个数. 首先是自己大致上能明白应该用动态规划的思想否则算法复杂度必然过大.可是对于回文串很难找到其状态和状态转移方程,换句话