关于map的定义: template < class Key, class T, class Compare = less<Key>, class Allocator = allocator<pair<const Key,T> > > class map; 第一个template参数被当做元素的key,第二个template参数被当作元素的value.Map的元素型别Key和T,必须满足以下两个条件:1.key/value必须具备assignable(可赋值
std::map插入已存在的key时,key对应的内容不会被更新,如果不知道这一点,可能会造成运行结果与预期的不一致 “Because element keys in a map are unique, the insertion operation checks whether each inserted element has a key equivalent to the one of an element already in the container, and if so, the
近期在看dnsjava 源码的时候,不经意间发现一个自己没有想过的问题: HashMap 如何使用key去查找对应的value的,这个问题很难用语言描述的清楚,那就使用代码来进行说明吧! public class test { public static void main(String[] args) { a aa = new a(); b bb = new b(); Map<Object,Object> c = new HashMap<Object,Object>(); c.p
From: https://www.walletfox.com/course/mapwithcustomclasskey.php If you have ever tried to use a custom class as a key of std::map, most probably you got a compilation error. This article explains why this happens and shows how to make custom classes