整数转化 牛客网 程序员面试金典 C++ Python 题目描述 编写一个函数,确定需要改变几个位,才能将整数A转变成整数B. 给定两个整数int A,int B.请返回需要改变的数位个数. 测试样例: 10,5 返回:4 C++ class Transform { public: //run:3ms memory:480k int calcCost(int A, int B) { int C = A^B; return getOneCount(C); } int getOneCount(int
Given an integer, convert it to a roman numeral. Input is guaranteed to be within the range from 1 to 3999. 之前那篇文章写的是罗马数字转化成整数(http://www.cnblogs.com/grandyang/p/4120857.html), 这次变成了整数转化成罗马数字,基本算法还是一样.由于题目中限定了输入数字的范围(1 - 3999), 使得题目变得简单了不少. 基本字符 I V
Roman numerals are represented by seven different symbols: I, V, X, L, C, D and M. Symbol Value I 1 V 5 X 10 L 50 C 100 D 500 M 1000 For example, two is written as II in Roman numeral, just two one's added together. Twelve is written as, XII, which i
面试题 分别给出下述代码在终端(e.g. IPyhon)中和在程序中的运行结果: a = 256 b = 256 c = 257 d = 257 def foo(): e = 257 f = 257 print('a is b: %s' % (a is b)) print('c is d: %s' % (c is d)) print('c is e: %s' % (c is e)) print('e is f: %s' % (e is f)) foo() IPython 中运行的结果: In [