declare @start date,@end date; set @start='2010-01-01'; set @end='2010-02-01'; --获取时间段内日期列表 select [day]=dateadd(day, number - 1, @start) from master.dbo.spt_values where type='P' and number <= datediff(day, @start,@end) + 1 and number>0
二话不说,先上图 实现如上代码: //获取本周第一天 showWeekFirstDay: function () { let Nowdate = new Date(); let WeekFirstDay = new Date(Nowdate - (Nowdate.getDay() - 1) * 86400000); let M = Number(WeekFirstDay.getMonth()) + 1; if (M < 10) { M = "0" + M; } let D = W
switch ($type){ case 'day'://当日 $end=date(,,,date(,date('Y'))); $where=' and '.$pre.'create_time>="'.date('Y-m-d').'" and '.$pre.'create_time<="'.$end.'"'; break; case 'week'://获取周数据:往前推6天 $week_start=date(,,,date(,date('Y'))); $
select convert(varchar(7),dateadd(month,number,'2010-01-01'),120) AS MONTHfrom master..spt_valueswhere type='P' and dateadd(month,number,'2010-01-01')<='2010-09-01'
,'2015-01-01 00:00:00') h INTO vinson_h DELETE vinson_h DECLARE @h int SELECT @h=DATEDIFF(HOUR,'2015-01-01 00:00:00',GETDATE()) WHILE(@num<=@h) BEGIN INSERT INTO vinson_h(h) values (DATEADD(HOUR,@num,'2015-01-01 00:00:00')) END SELECT * FROM vinson_h
public static void main(String[] args) { SimpleDateFormat dateFormat = new SimpleDateFormat("yyyy-MM-dd"); String dateFirst="2017-05-01"; String dateSecond="2017-05-25"; try{ Date st
/// 当前月有多少天 /// </summary> /// <param name="y"></param> /// <param name="m"></param> /// <returns></returns> public static int HowMonthDay(int y, int m) { int mnext; int ynext; ) { mnext = m +
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