待补充:https://www.cnblogs.com/zknublx/p/6042295.html 一.使用集合直接去重 ids = [1,4,3,3,4,2,3,4,5,6,1]ids = list(set(ids)) 处理起来比较简单,使用了集合方法set进行处理,不过结果不会保留之前的顺序. 二.列表法 ids = [1,2,3,3,4,2,3,4,5,6,1]news_ids = []for id in ids: if id not in news_ids: new
26. Remove Duplicates from Sorted Array Given a sorted array, remove the duplicates in place such that each element appear only once and return the new length. Do not allocate extra space for another array, you must do this in place with constant mem
A题,题目链接:http://codeforces.com/contest/978/problem/A 解题心得:题意就是让你将这个数列去重,重复的数只保留最右边的那个,最后按顺序打印数列.set+map. #include <bits/stdc++.h> using namespace std; const int maxn = 100; int num[maxn],n; map <int,int> map1,map2; set <int> se; int main(
在SQL语言中去重是一件相当简单的事情,面对一个表(也可以称之为DataFrame)我们对数据进行去重只需要GROUP BY 就好. select custId,applyNo from tmp.online_service_startloan group by custId,applyNo 1.DataFrame去重 但是对于pandas的DataFrame格式就比较麻烦,我看了其他博客优化了如下三种方案. 我们先引入数据集: import pandas as pd data=pd.read_
数据转换 移除重复数据 import pandas as pd import numpy as np from pandas import Series data = pd.DataFrame( {'k1':['one']*3+['two']*4, 'k2':[1,1,2,3,3,4,4]}) data k1 k2 0 one 1 1 one 1 2 one 2 3 two 3 4 two 3 5 two 4 6 two 4 duplicated方法返回一个布尔型Series,表示各行是否是重复