C - Prime number or not Time Limit:2000MS Memory Limit:32768KB 64bit IO Format:%I64d & %I64u Submit Status Practice FZU 1649 Description Your task is simple.Give you a number N, you should judge whether N is a prime number or not. Input There
1552: Friends Time Limit: 3 Sec Memory Limit: 256 MBSubmit: 163 Solved: 34[Submit][Status][Web Board] Description On an alien planet, every extraterrestrial is born with a number. If the sum of two numbers is a prime number, then two extraterrestri
Problem about GCD Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 470 Accepted Submission(s): 77 Problem Description Given integer m. Find multiplication of all 1<=a<=m such gcd(a, m)=1 (cop
import math from functools import reduce #用于合并字符 from os import urandom #系统随机的字符 import binascii #二进制和ASCII之间转换 #=========================================== def Mod_1(x,n): '''取模负1的算法:计算x2= x^-1 (mod n)的值, r = gcd(a, b) = ia + jb, x与n是互素数''' x0 = x
#include<iostream> #include<cstdio> #include<ctime> #include<string.h> #include<stdlib.h> #define LL long long using namespace std; const int S=20;//随机算法判定次数,S越大,判错概率越小 LL ans; //给定一个数,判断是否是素数(常用long long大数) LL mult_mod(LL a,