1. 用1阶至4阶Newton-Cotes公式计算积分 程序: function I = NewtonCotes(f,a,b,type) % syms t; t=findsym(sym(f)); I=0; switch type case 1, I=((b-a)/2)*(subs(sym(f),t,a)+subs(sym(f),t,b)); case 2, I=((b-a)/6)*(subs(sym(f),t,a)+4*subs(sym(f),t,(a+b)/2)+... subs(sym(f)
1806: Toll Time Limit: 5 Sec Memory Limit: 128 MB Special JudgeSubmit: 256 Solved: 74[Submit][Status][Web Board] Description In ICPCCamp, there are n cities and m unidirectional roads between cities. The i-th road goes from the ai-th city to the
Ellipse Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 1977 Accepted Submission(s): 832 Problem Description Math is important!! Many students failed in 2+2’s mathematical test, so let's AC t
1.KMP #include<cstring> #include<algorithm> #include<cstdio> using namespace std; const int maxn=1e6; ],b[maxn+]; ]; int len1,len2,t; int main() { scanf("%d\n",&t); while(t) { --t; scanf("%s%s",b,a);//a是母串 b是匹配串 l
Two Cylinders Special JudgeTime Limit: 10000/5000MS (Java/Others)Memory Limit: 128000/64000KB (Java/Others) SubmitStatisticNext Problem Problem Description In this problem your task is very simple. Consider two infinite cylinders in three-dimensional
The area Time Limit:1000MS Memory Limit:32768KB 64bit IO Format:%I64d & %I64u Submit Status Description Ignatius bought a land last week, but he didn't know the area of the land because the land is enclosed by a parabola and a straight line.