1)使用join 和 rand() 耗时 0.009 SELECT * FROM `t_topic` AS t1 JOIN ( SELECT ROUND( RAND() * ( (SELECT MAX(id) FROM `t_topic`) - (SELECT MIN(id) FROM `t_topic`) ) + (SELECT MIN(id) FROM `t_topic`) ) AS id ) AS t2 WHERE t1.id >= t2.id ORDER BY t1.id LIMIT ;
Mysql每天执行计划,保留最新的10条数据,其余的删除 1.Mysql 保留最新的10条数据 sql语句: DELETE tb FROM tbname AS tb,( SELECT id FROM tbname ORDER BY id desc LIMIT 9,1 ) AS tmp WHERE tb.id<tmp.id 2.新建存储过程(Navicat中) CREATE PROCEDURE test() BEGIN DELETE tb FROM testdata AS tb,( SELECT
在sql server中,取数据中前10条语句,我们可以用top 10 这样语句,但是oracle就没有这个函数,接下来介绍它们之间的区别 1.sql server 取前10语句和随机10条的语法 --测试表数据-- select * from BdsPaperItem --查询测试表的前10条语句-- * from BdsPaperItem order by Uid asc --随机查询测试表10条语句-- * from BdsPaperItem order by NEWID() 结果实例:
在实际用途中,常常会要求取最近的几条纪录,这就需要先对纪录进行排序后再取rownum <= 一般常见的 SELECT * FROM (SELECT a.* FROM torderdetail a ORDER BY order_date DESC) WHERE ROWNUM <= 10 而在CSDN曾经发生过讨论,关于取近的10条纪录,有人给出这样的语句 SELECT a.* FROM torderdetail a WHERE ROWNUM <= 10 ORDER BY order_dat
SELECT ATA FROM LM_FAULT WHERE ( OCCUR_DATE BETWEEN to_date( '2017-05-01', 'yyyy-MM-DD' ) AND to_date( '2017-05-15', 'yyyy-MM-DD' ) ) ORDER BY ATA ASC ; 修改如下 不忘初心,如果您认为这篇文章有价值,认同作者的付出,可以微信二维码打赏任意金额给作者(微信号:382477247)哦,谢谢.
第一种方法:效率最高 SELECT TOP 页大小 * FROM ( SELECT ROW_NUMBER() OVER (ORDER BY id) AS RowNumber,* FROM table1 ) as A ) --注解:首先利用Row_number()为table1表的每一行添加一个行号,给行号这一列取名'RowNumber' 在over()方法中将'RowNumber'做了升序排列 --然后将'RowNumber'列 与table1表的所有列 形成一个表A --重点在where条件.