POJ 2195 Going Home (带权二分图匹配) Description On a grid map there are n little men and n houses. In each unit time, every little man can move one unit step, either horizontally, or vertically, to an adjacent point. For each little man, you need to pay a
这是一道代码大题.一开始读错题意了,然后理解成直接看上去的那种相邻,然后想不通好久!!! 把不同联通的图分离出来,然后先预处理一下形成之后的相邻图的状态,然后根据01确定哪一些是需要更换状态的,然后建图,利用二分图KM算法去匹配最优方案.然后求出每一组更换的,利用原先已经求好的路径去储存答案. #include<bits/stdc++.h> using namespace std; const int inf = 0x3f3f3f3f; ; vector<pair<int, int
How far away ? Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 28961 Accepted Submission(s): 11639 Problem Description There are n houses in the village and some bidirectional roads connectin