import java.math.BigDecimal; public class TestGetInt { public static void main(String[] args) { double i = 2, j = 2.1, k = 2.5, m = 2.9; System.out.println("舍掉小数取整:Math.floor(2)=" + ( System.out.println("舍掉小数取整:Math.floor(2.1)=" + ( Sy
package ltb6w1; import java.io.*; public class TestMod { String st; int c; InputStreamReader is=new InputStreamReader(System.in); BufferedReader bf=new BufferedReader(is); public TestMod() throws IOException { System.out.println("请输入整数:"); while
向上取整用Math.ceil(double a) 向下取整用Math.floor(double a) 举例: public static void main(String[] args) throws Exception { double a = 35; double b = 20; double c = a / b; System.out.println("c===>" + c); // 1.75 System.out.println("c===>"
1.考虑不重复元素,重复元素不添加 import java.awt.List; import java.util.ArrayList; import java.util.TreeSet; public class Solution { public static int[] intersection(int[] nums1,int[] nums2){ TreeSet<Integer> set =new TreeSet<>(); for(int num : nums1)//把不重复的
有时候,可能会有一些类似这样的需求: 对于这样的效果,我们可以有类似这样的解决方案: package bys.utils; import java.io.UnsupportedEncodingException; /** * Created by toutou on 2014/2/21 */ public class ChineseCharacterHelper { static final int GB_SP_DIFF = 160; // 存放国标一级汉字不同读音的起始区位码 static f
public class TimestampLength { public static void main(String[] args) { System.out.println(java.nio.charset.Charset.defaultCharset().toString()); System.out.println("学java".getBytes().length); System.out.println("2018-11-27 02:24:00.0000000