多线程下,两个线程交替打印0 -100,使用wait()和notify() public class ThreadTest{ private static final Object lock = new Object(); static class ThreadA extends Thread{ @Override public void run() { for (int i = 0; i < 100; i = i+2) { synchronized (lock){ lock.notify();
简要分析: 要求三个线程轮流输出,这里我们要使用一个对象锁,让关键部分的代码放入同步块当中.同时要有一个变量记录打印的次数到达10次循环后不再打印,另外一个就是要给每个线程一个标志号,我们根据标识号来输出对应的信息. package com.test; public class PrintOneTwoThree { public static void main(String[] args) { Print p1 = new Print(0); Print p2 = new Print(1);
题目:3个线程名字分别是A,B,C 现在在console上连续打印10次 ABC . public class Test { public static void main(String[] args) { Thread a = new Thread(new Task("A",0)); Thread b = new Thread(new Task("B",1)); Thread c = new Thread(new Task("C",2)); a
方案一:import java.util.concurrent.locks.Condition;import java.util.concurrent.locks.Lock;import java.util.concurrent.locks.ReentrantLock; /** * created by cjy * desc: lock and condition */public class Test100_01 { private static Lock lock = new Reentra
import threading con = threading.Condition() word = u"12345上山打老虎" def work(): global word con.acquire() while True: print word[0] word = word[1:] if len(word) == 0: break con.notify() if len(word) == 1: break con.wait() con.release() t1 = thread
https://blog.csdn.net/weixin_39723337/article/details/80352783 题目:3个线程循环打印ABC,其中A打印3次,B打印2次,C打印1次,循环打印2轮一.Synchronized同步法思路:使用synchronized.wait.notifyAll的方法利用线程标记变量控制三个线程的执行顺序. /** * @author XDarker * 2018-5-17 */public class Main { public static voi