利用α-β剪枝算法,对下图所示的博弈树进行搜索,搜索得到根节点选择的走步,以及没有必要进行评估的节点,并求出给出在何处发生了剪枝,以及剪枝的类型(属于α剪枝还是β剪枝). 注:□表示MIN节点:○表示MAX节点 public interface Interface{ public void getStrategy(String InputFile); } import java.util.*; import java.io.*; public class AlphaBeta implements
Black And White Time Limit: 2000/2000 MS (Java/Others) Memory Limit: 512000/512000 K (Java/Others) Total Submission(s): 929 Accepted Submission(s): 238 Special Judge Problem Description In mathematics, the four color theorem, or the four color map th
Problem Description The doggie found a bone in an ancient maze, which fascinated him a lot. However, when he picked it up, the maze began to shake, and the doggie could feel the ground sinking. He realized that the bone was a trap, and he tried despe
题目大意:输入三个整数N,M,T.在接下来的N行.M列会有一系列的字符.其中S表示起点,D表示终点. .表示路 . X表示墙...问狗能有在T秒时到达D.如果能输出YES, 否则输出NO 解题思路:DFS+剪枝 代码如下: /* * 1010_3.cpp * * Created on: 2013年8月16日 * Author: Administrator */ #include <iostream> using namespace std; bool flag; int N, M, T; in
Red and Black Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 12519 Accepted Submission(s): 7753 Problem Description There is a rectangular room, covered with square tiles. Each tile is color
A - A + B Problem II I have a very simple problem for you. Given two integers A and B, your job is to calculate the Sum of A + B. Input The first line of the input contains an integer T(1<=T<=20) which means the number of test cases. Then T lines fo
题意简述 给出n个数,求最小的l,使n个数可分成若干组,每组和都为l. 题解思路 暴力搜索+剪枝 代码 #include <cstdio> #include <cstdlib> #include <algorithm> using namespace std; int n, sum, minn, maxx; int t[70]; void dfs(int gs, int last, int sy, int qb) { if (gs == 0) { printf(&quo