A Simple Problem with Integers Time Limit: 5000MS Memory Limit: 131072K Total Submissions: 97217 Accepted: 30358 Case Time Limit: 2000MS Description You have N integers, A1, A2, ... , AN. You need to deal with two kinds of operations. One type of
Matrix Time Limit: 3000MS Memory Limit: 65536K Total Submissions: 17766 Accepted: 6674 Description Given an N*N matrix A, whose elements are either 0 or 1. A[i, j] means the number in the i-th row and j-th column. Initially we have A[i, j] = 0 (1
A Simple Problem with Integers Time Limit: 5000MS Memory Limit: 131072K Total Submissions: 47174 Accepted: 13844 Case Time Limit: 2000MS Description You have N integers, A1, A2, ... , AN. You need to deal with two kinds of operations. One type of
Color the ball Time Limit: 9000/3000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 17044 Accepted Submission(s): 8513 Problem Description N个气球排成一排,从左到右依次编号为1,2,3....N.每次给定2个整数a b(a <= b),lele便为骑上他的“小飞鸽"牌电动车从气
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=4031 Attack Time Limit: 5000/3000 MS (Java/Others) Memory Limit: 65768/65768 K (Java/Others) Total Submission(s): 1890 Accepted Submission(s): 554 Problem Description Today is the 10th Annual of "S
Color the ball Time Limit: 9000/3000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 8984 Accepted Submission(s): 4594 Problem Description N个气球排成一排,从左到右依次编号为1,2,3....N.每次给定2个整数a b(a <= b),lele便为骑上他的“小飞鸽"牌电动车从气球
题意:给你一个n*n的全0矩阵,每次有两个操作: C x1 y1 x2 y2:将(x1,y1)到(x2,y2)的矩阵全部值求反 Q x y:求出(x,y)位置的值 树状数组标准是求单点更新区间求和,但是我们处理一下就可以完美解决此问题.区间更新可以使用区间求和的方法,在更新的(x2,y2)记录+1,在更新的(x1-1,y1-1)-1(向前更新到最前方).单点求和就只需要与区间更新相反,向后求一个区间和.这样做的理由是:如果求和的点在某次更新范围内,我们+1但是不执行-1,否者要么都不执行,要么都