453. 最小移动次数使数组元素相等 给定一个长度为 n 的非空整数数组,找到让数组所有元素相等的最小移动次数.每次移动可以使 n - 1 个元素增加 1. 示例: 输入: [1,2,3] 输出: 3 解释: 只需要3次移动(注意每次移动会增加两个元素的值): [1,2,3] => [2,3,3] => [3,4,3] => [4,4,4] class Solution { public int minMoves(int[] nums) { int moves = 0, min = In
Given a non-empty integer array, find the minimum number of moves required to make all array elements equal, where a move is incrementing a selected element by 1 or decrementing a selected element by 1. You may assume the array's length is at most 10
交换相邻两数 如果只是交换相邻两数,那么最少交换次数为该序列的逆序数. 交换任意两数 数字的总个数减去循环节的个数?? A cycle is a set of elements, each of which is in the place of another. So in example sequences { 2, 1, 4, 3}, there are two cycles: {1, 2} and {3, 4}. 1 is in the place where 2 needs to G
public class CountJava{ public static void main(String[] args){ String str = "dnajjavaNISLjavaERBjavafvsbdjavaFALjavaEUIcjavazs"; int count = 0; int index = 0; while(str.indexOf("java") != -1){ index = str.indexOf("java"); st
Given a non-empty integer array of size n, find the minimum number of moves required to make all array elements equal, where a move is incrementing n - 1 elements by 1. Example: Input: [1,2,3] Output: 3 Explanation: Only three moves are needed (remem
给一个矩阵mat,每个格子都是0或1,翻转一个格子会将该格子以及相邻的格子(有共同边)全部翻转(0变为1,1变为0) 求问最少需要翻转几次将所有格子全部置为0. 这题的重点是数据范围,比赛结束看了眼数据范围想把自己锤死= = m == mat.length n == mat[0].length 1 <= m <= 3 1 <= n <= 3 mat[i][j] is 0 or 1. 也就是....最多也就9个格子.....暴力怎么都能搞出来的..... 首先分析每个格子要么