问题: 设计一函数,求整数区间[a,b]和[c,d]的交集.(c/c++.Java.Javascript.C#.Python) 1.Python: def calcMixed(a,b,c,d): rtn=[] list1=range(a,b+1) for num in range(c,d+1): if num in list1: rtn.append(num) return rtn mixed=calcMixed(1,8,5,9) print(mixed) 2.
先看看这个题目:某整形数组中除了两个单身整数外, 其余的整数都是成对出现的, 利用C代码求出这两个单身整数. 要求: 时间复杂度o(n), 空间复杂度o(1). 我们先用最傻瓜的方式来做吧: #include <iostream> using namespace std; // 时间复杂度为o(n^2), 空间复杂度为o(1), 不符合要求 void findSoleNumbers(int a[], int n, int &e1, int &e2) { int i = 0; i
/// <summary> /// 整数区间类 /// </summary> private class Interval { , _end = ; public int Start { get { return Math.Min(this._start, this._end); } set { this._start = value; } } public int End { get { return Math.Max(this._start, this._end); } set
题目链接:https://www.nowcoder.com/acm/contest/141/H 时间限制:C/C++ 1秒,其他语言2秒 空间限制:C/C++ 262144K,其他语言524288K 64bit IO Format: %lld 题目描述 Eddy has solved lots of problem involving calculating the number of coprime pairs within some range. This problem can be so
#include<bits/stdc++.h>using namespace std;const long long mod = 998244353;typedef const long long ll;vector<long long>p;long long inv(long long x,long long y)//快速幂求逆元模板(以乘代除){ long long r=1; while(y>0) { if(y&1)
Carmichael Numbers An important topic nowadays in computer science is cryptography. Some people even think that cryptography is the only important field in computer science, and that life would not matter at all without cryptography. Alvaro is one
洛谷P1440 求m区间内的最小值 ............................................................................... 以上代表我此时的心情,调了一个小时....只因为顺序,维护一个单调递增队列就好了,这里n很大,输出要优化,这才挽救了30分.. #include<bits/stdc++.h> using namespace std; int n,m; ],q[]; int top,tai; void Cin(int