Given a non-empty integer array of size n, find the minimum number of moves required to make all array elements equal, where a move is incrementing n - 1 elements by 1. Example: Input: [1,2,3] Output: 3 Explanation: Only three moves are needed (remem
给定一个长度为 n 的非空整数数组,找到让数组所有元素相等的最小移动次数.每次移动可以使 n - 1 个元素增加 1.示例:输入:[1,2,3]输出:3解释:只需要3次移动(注意每次移动会增加两个元素的值):[1,2,3] => [2,3,3] => [3,4,3] => [4,4,4]详见:https://leetcode.com/problems/minimum-moves-to-equal-array-elements/description/ C++: class S
453. 最小移动次数使数组元素相等 给定一个长度为 n 的非空整数数组,找到让数组所有元素相等的最小移动次数.每次移动可以使 n - 1 个元素增加 1. 示例: 输入: [1,2,3] 输出: 3 解释: 只需要3次移动(注意每次移动会增加两个元素的值): [1,2,3] => [2,3,3] => [3,4,3] => [4,4,4] class Solution { public int minMoves(int[] nums) { int moves = 0, min = In
There are two sorted arrays nums1 and nums2 of size m and n respectively. Find the median of the two sorted arrays. The overall run time complexity should be O(log (m+n)). You may assume nums1 and nums2 cannot be both empty. Example 1: nums1 =
We have two integer sequences A and B of the same non-zero length. We are allowed to swap elements A[i] and B[i]. Note that both elements are in the same index position in their respective sequences. At the end of some number of swaps, A and B are b
[抄题]: We have two integer sequences A and B of the same non-zero length. We are allowed to swap elements A[i] and B[i]. Note that both elements are in the same index position in their respective sequences. At the end of some number of swaps, A and B