function DX(n) { if (!/^(0|[1-9]\d*)(\.\d+)?$/.test(n)) return "数据非法"; var unit = "千百拾亿千百拾万千百拾元角分", str = ""; n += "00"; var p = n.indexOf('.'); if (p >= 0) n = n.substring(0, p) + n.substr(p+1, 2); unit = unit.s
var digitUppercase = function(n) { var fraction = ['角', '分']; var digit = [ '零', '壹', '贰', '叁', '肆', '伍', '陆', '柒', '捌', '玖' ]; var unit = [ ['元', '万', '亿'], ['', '拾', '佰', '仟'] ]; var head = n < 0 ? '欠' : ''; n = Math.abs(n); var s = ''; for (var i
(非原创, 来自网络,仅作收藏) var digitUppercase = function(n) { var fraction = ['角', '分']; var digit = [ '零', '壹', '贰', '叁', '肆', '伍', '陆', '柒', '捌', '玖' ]; var unit = [ ['元', '万', '亿'], ['', '拾', '佰', '仟'] ]; var head = n < 0 ? '欠' : ''; n = Math.abs(n); var s
1.问题1 执行下列SQL: sql = "select count(1) as totle from vhl_model_data a where a.OBTAIN_CREATE_TIME between to_date(?,'yyyymmsshh24mi') and to_date(?,'yyyymmsshh24mi');"; Oracle报“无效数字异常”:经过两个钟头的反复的检查,发现是由于自己粗心在上述语句结尾多写了个分号“;”导致.粗心害死人啊!真是囧! 2.问题2 ORA
写出将字符串中的数字转换为整型的方法,如:"as31d2v"->312,并写出相应的单元测试,输入超过int范围时提示不合法输入. public struct ConvertResult { public ConvertState State; public int Number; } public enum ConvertState { // 输入不合法 InValid = , // 输入合法 Valid = } public class StringHelper { publ
C语言提供了几个标准库函数,可以将任意类型(整型.长整型.浮点型等)的数字转换为字符串.以下是用itoa()函数将整数转换为字符串的一个例子: # include <stdio. h># include <stdlib. h>void main (void);void main (void){ int num = 100; char str[25]; itoa(num, str, 10); printf("The number 'num' is %