Given an integer array nums, return the number of range sums that lie in [lower, upper] inclusive.Range sum S(i, j) is defined as the sum of the elements in nums between indices i and j (i ≤ j), inclusive. Note:A naive algorithm of O(n2) is trivial.
题目连接:http://acm.hust.edu.cn/vjudge/problem/viewProblem.action?id=19461 Game of sum Description This is a two player game. Initially there are n integer numbers in an array and players A and B getchance to take them alternatively. Each player can take
题目连接:10891 - Game of Sum 题目大意:有n个数字排成一条直线,然后有两个小伙伴来玩游戏, 每个小伙伴每次可以从两端(左或右)中的任意一端取走一个或若干个数(获得价值为取走数之和), 但是他取走的方式一定要让他在游戏结束时价值尽量的高,最头疼的是两个小伙伴都很聪明,所以每一轮两人都将按照对自己最有利的方法去取数字,请你算一下在游戏结束时,先取数的人价值与后取数人价值之差(不要求绝对值). 解题思路:这道题目想了一晚上,死憋着不看题解, 结果写出的代码有点渣,dpx[i][j]
Given an integer array nums, return the number of range sums that lie in [lower, upper] inclusive.Range sum S(i, j) is defined as the sum of the elements in nums between indices i and j (i ≤ j), inclusive. Note:A naive algorithm of O(n2) is trivial.
D. Mishka and Interesting sum time limit per test 3.5 seconds memory limit per test 256 megabytes input standard input output standard output Little Mishka enjoys programming. Since her birthday has just passed, her friends decided to present her wit
Given an integer array nums, return the number of range sums that lie in [lower, upper] inclusive.Range sum S(i, j) is defined as the sum of the elements in nums between indices i and j (i ≤ j), inclusive.Note:A naive algorithm of O(n2) is trivial. Y
开始以为是水题,结果...... 给你一些只有两种颜色的石头,0为白色,1为黑色. 然后两个操作: 1 l r 将[ l , r ]内的颜色取反 0 l r 计算[ l , r ]内最长连续黑色石头的个数 明显的线段树区间合并,记录lmax(从左端点开始的最长值) rmax(从右端点开始的最长值) 用于更新mmax(区间最长值) 但是这儿有区间更新,所以记录0的三个最长值和1的三个最长值,更新父节点的时候交换0与1就好. 还有这儿注意查询时,可能值在查询的几个子区间的的相邻处(因为我们只能查
Billboard Time Limit: 20000/8000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 21203 Accepted Submission(s): 8750 Problem Description At the entrance to the university, there is a huge rectangular billboard of
无指针Splay超详细讲解 区间树这玩意真TM玄学. 学这东西你必须要拥有的 1.通过[模板]文艺平衡树(Splay),[模板]普通平衡树,GSS3 - Can you answer these queries III 2.学会Splay,学会求最大子段和并知道怎么维护信息和下传标记,及会有区间修的最大子段和 3.多年的编程技巧,以及一颗写数据结构的良好心态 4.攒够两个月的肝,这很重要! 如果你不会上面东西的解决方法 1.看以下博客Splay入门解析,文艺平衡树Splay题解,GSS系列题解-
Wow! Such Sequence! Time Limit: 10000/5000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others) Total Submission(s): 3808 Accepted Submission(s): 1079 Problem Description Recently, Doge got a funny birthday present from his new friend, Protein
ID Origin Title 228 / 440 Problem A HDU 1166 敌兵布阵 207 / 438 Problem B HDU 1754 I Hate It 181 / 727 Problem C POJ 3468 A Simple Problem with Integers 105 / 410 Problem D POJ 2528 Mayor's posters 138 / 230 Problem E HDU 1698 Just a Hook