for i, (input, target) in enumerate(trainloader): # measure data loading time data_time.update(time.time() - end) input, target = input.cuda(), target.cuda() if i==2: def for_hook(module,input, output): print('output values:',output) handle2 = model.
1.首先对给的数据进行划分,类型为每个类单独放在一个文件夹中 import json import shutil import os from glob import glob from tqdm import tqdm # 此文件的作用是创建每个类的文件夹,以及根据给出来的Json中已经做好的分类,对数据进行对号入座划分. # 加载json文件得出一个字典,然后根据Key值来提取每个文件到相应的文件夹中,(注意去除了不合理数据) try: for i in range(0,59): os.mk
1.递归,数组选出最大值 var arr = [9,8,55,66,49,68,109,55,33,6,2,1]; var max = arr[0]; function findMax( i ){ if( i == arr.length ) return max; if( max < arr[i] ) max = arr[i]; findMax(i+1);} findMax(1);console.log(max); 2.(博学谷视频--高级面向对象视频教程) 之第一季和第二集 <!doctyp
给个人认为比较难的题目打上'*' NOIP2002(clear) //一个很吼的贪心题,将平均数减掉之后从左往右将影响消除 #include<bits/stdc++.h> using namespace std; ]; int main() { , sum = ; cin >> n; ; i < n ; i++) { cin >> num[i]; sum += num[i]; } sum /= n; ; i < n ; i++) { num[i] -= su
Description Let's play a puzzle using eight cubes placed on a 3 × 3 board leaving one empty square. Faces of cubes are painted with three colors. As a puzzle step, you can roll one of the cubes to a adjacent empty square. Your goal is to make the spe