//数组中找两个最小值,及索引 //例如数组: [2,6,7,4,10,3,5]; 计算得出,min1=2,index1=0,min2=3,index2=5; var min1 = Infinity; var min2 = min1; var index1 = -1; var index2 = -1; var arr = [2,6,7,4,10,3,5]; for(var i = 0; i < arr.length; i++ ){ var item = arr[i]; if(item < mi
class MyArray: '''保证输入的内容是整型.浮点型''' def ___isNumber(self, num): if not isinstance(num, (int,float)): return False return True #开始写构造函数,接受可变长度的数组 def __init__(self, *args): if args == None: self.__value = [] else: for a in args: if not self.___isNumbe
//在两个数成对出现的数组中找到一个单独的数.比如{1,2,3.3,1,4.2},即找出4 #include <stdio.h> int find(int arr[], int len) { int i = 0; int ret = 0; for (i = 0; i < len; i++) { ret = ret^arr[i]; } return ret; } int main() { int arr1[] = { 1, 2, 2, 3, 1, 5, 3 }; int arr2[] =