public static List<GCountryExtend> GetList() { try { var result = new List<GCountryExtend>(); using (ServiceManager<IGCountry> sm = new ServiceManager<IGCountry>()) { result = sm.Service.GetExtendListByWhere(string.Empty); //处理中国优先
function getSearchString(key) { // 获取URL中?之后的字符 var str = location.search; str = str.substring(1,str.length); // 以&分隔字符串,获得类似name=xiaoli这样的元素数组 var arr = str.split("&"); var obj = new Object(); // 将每一个数组元素以=分隔并赋给obj对象 for(var i = 0; i &l
Leftmost Digit Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 20361 Accepted Submission(s): 7864 Problem Description Given a positive integer N, you should output the leftmost digit of N^N.
/** * 获取URL中指定参数的值 * * @param name 参数名称 * @returns */ function getQueryString(name) { var reg = new RegExp('(^|&)' + name + '=([^&]*)(&|$)', 'i'); var r = window.location.search.substr(1).match(reg); if (r != null) { return unescape(r[2]); } r
oracle中创建sequence指定起始值 DECLARE V_Area_Id NUMBER; BEGIN SELECT MAX(T.Area_Id)+10 INTO V_Area_Id FROM T_PM_TankArea T; if V_Area_Id is null THEN select 1 into V_Area_Id from dual; END IF; EXECUTE IMMEDIATE 'create sequence S_PM_TankArea minvalue 1 maxv
变量mynation从列表{"china", "US", "UK"}中随机取值 String[] nation = new String[]{"china", "US", "UK"}; Random random = new Random(); int i = random.nextInt(nation.length); vars.put("mynation",nat