18岁生日 Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 23314 Accepted Submission(s): 7461 Problem Description Gardon的18岁生日就要到了,他当然很开心,可是他突然想到一个问题,是不是每个人从出生开始,到达18岁生日时所经过的天数都是一样的呢?似乎并不全都是这样,所以他
18岁生日 Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 16784 Accepted Submission(s): 5317 Problem Description Gardon的18岁生日就要到了,他当然很开心,可是他突然想到一个问题,是不是每个人从出生开始,到达18岁生日时所经过的天数都是一样的呢?似乎并不全都是这样,所以他
18岁生日 Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 23411 Accepted Submission(s): 7494 Problem Description Gardon的18岁生日就要到了,他当然非常开心,但是他突然想到一个问题,是不是每一个人从出生開始.到达18岁生日时所经过的天数都是一样的呢?似乎并不全都是这样,
package java1; public class People { public String name; public int age; public String sex; public String height; People(String name, int age, String sex, String height) { this.name = name; this.age = age; this.sex = sex; this.height = height; } publ
package com.chuoji; public class People { private String name; private int age; private String sex; private double height; public String getName() { return name; } public void setName(String name) { this.name = name; } public int getAge() { return ag
--- //查找左边不存在数据,不能用 = '' SELECT m.uid FROM es_members m LEFT JOIN es_user_self_care_assessment u ON m.uid = u.user_id WHERE u.user_id IS NULL //合并起来查找 #(, )) as n 计算出年龄 SELECT m.uid,(, )) as n FROM es_members m LEFT JOIN es_user_self_care_assessment
SELECT *, Age= datediff(yy,cast(case when substring(PersonalId,,) ') /*若第7位不是'1'或'2'则表示是15位身份证编码规则*/ then substring(PersonalId,,) ,) end as datetime),getdate()) FROM Student WHERE datediff(yy,cast(case when substring(PersonalId,,) ') then substring(P