UPDATE `TB_CM_Dic` SET `ParentID` = (SELECT `ID` FROM (SELECT * FROM `TB_CM_Dic`) AS B WHERE `DicName` = '药品类别') WHERE `ID` = ( SELECT `ID` FROM( SELECT * FROM `TB_CM_Dic` WHERE `DicName` = '日常用品' AND `ParentID` = ( SELECT `ID` D FROM `TB_CM_Dic` D W
1.insert select from <一棵树-博客园> 收集整理,转载请注明出处! 使用SELECT INTO 和 INSERT INTO SELECT 表复制语句了. 1.INSERT INTO SELECT语句 语句形式为:Insert into Table2(field1,field2,...) select value1,value2,... from Table1 [where column =value][]为可选内容要求目标表Table2必须在由于目标表Table2已经存在
最常用的update语法是: UPDATE <table_name> SET <column_name1> = <value>, SET <column_name2> = <value> where 条件 如果我的更新值Value是从一条select语句拿出来,而且有很多列的话,用这种语法就很麻烦第一,要select出来放在临时变量上,有很多个哦第二,再将变量进行赋值.列多起来非常麻烦,能不能像Insert那样,把整个Select语句的结果进
1. SELECT语句的子查询 语法: SELECT ... FROM (subquery) AS name ... 先创建一个表: CREATE TABLE t1 (s1 INT, s2 CHAR(5), s3 FLOAT);INSERT INTO t1 VALUES (1,'1',1.0);INSERT INTO t1 VALUES (2,'2',2.0); 我们就可以进行以下的嵌套查询了:SELECT sb1,sb2,sb3 FROM (SELECT s1 AS sb1
mysql中不支持嵌套查询后更新操作. 但是可以使用inner join来解决自身的更新问题,参考如下例子: update hera_job a inner join( ),'"') as script_new from hera_job ) b set a.script = b.script_new ,) = 'sh' and a.id = b.id
正确写法: update 别名 set 别名点字段 =xxxx UPDATE a SET a.StandardID = (SELECT b.StandardID FROM SurgeryMappingRecycle b, SurgeryMappingHistory c WHERE a.ID = b.ID) FROM SurgeryMappingHistory a 错误写法: '
UPDATE t_user INNER JOIN t_shake ON t_shake.user_id = t_user.user_id SET t_user.shake_total_num = t_shake.shake_total_num; UPDATE t_user INNER JOIN ( select user_id,count(id) as share_total_num from `t_share_history` group by user_id ) tmp ON tmp.use