Given an encoded string, return it's decoded string. The encoding rule is: k[encoded_string], where the encoded_stringinside the square brackets is being repeated exactly k times. Note that kis guaranteed to be a positive integer. You may assume that
[译文] 摘要:为一个简单的有漏洞程序写一个简单的缓冲区溢出EXP,聚焦于遇到的问题和关键性的教训,提供详细而彻底的描述 内容表:1. I pity the fool, who can't smash the stack:--介绍&背景2.Welcome to the jungle, we've got fun and wargames:--介绍我们之后要使用的示例&分析它的源代码3. There is no spoon. This causes problems when you try
栈是先进后出,后进先出的操作. 有点类似浏览器返回上一页的操作, public class Stack<E>extends Vector<E> 是vector的子类. 常用方法: boolean empty() 测试堆栈是否为空. E peek() 查看堆栈顶部的对象,但不从堆栈中移除它. E pop() 移除堆栈顶部的对象,并作为此函数的值返回该对象. E push(E item) 把项压入堆栈
1. Description Given a list of airline tickets represented by pairs of departure and arrival airports [from, to], reconstruct the itinerary in order. All of the tickets belong to a man who departs from JFK. Thus, the itinerary must begin with JFK. No
最近开始研究http 特别是multipart 表单,想弄明白他是怎么work 的.在nodejs 里,可以使用form-data 来组合一个multipart 表单,然后使用http.request 发送出去 var formData = require('form-data'); var http = require('http'); var urlParse = require('url').parse; var fs = require('fs'); f = new formData()
(function () { //check the class name , it will be replaced when existed if (window.IQCBase) { //return window.IQCBase; //window._IQCBase = window.IQCBase; } //constructor window.IQCBase = function (param) { param = param instanceof Object ? param :