#用strip(),split()两个方法都可以判断空行 infile=open('/.../','r') outfile=open('/.../','w') for li in infile.readlines(): if li.split(): #if li.strip(): outfile.writelines(li) infile.close() outfile.close()
统计难题 Time Limit: 4000/2000 MS (Java/Others) Memory Limit: 131070/65535 K (Java/Others)Total Submission(s): 16905 Accepted Submission(s): 7273 Problem Description Ignatius最近遇到一个难题,老师交给他很多单词(只有小写字母组成,不会有重复的单词出现),现在老师要他统计出以某个字符串为前缀的单词数量(单词本身也是自己的前
1)接收输入 check_status() { echo --Check hi_repo status is ok? y or n read var if [ "$var" != "y" ] then echo --input is not 'y' exit fi } 1.编写函数check_status,调用时直接写check_status,不用括号: 2.输入read var, 使用时用$var 3.if判断,可以用!=,注意if []的空格: 2)删除空行 #