public final class Math extends Object public static double floor(double a) public static long round(double a) public static int round(float a) public static double ceil(double a) floor 返回不大于的最大整数;ceil 则是不小于他的最小整数;round 它表示"四舍五入"
http://www.sebug.net/vuldb/ssvid-89680#0-tsina-1-18081-397232819ff9a47a7b7e80a40613cfe1 http://10.211.55.3/joomla/index.php?option=com_contenthistory&view=history&list[ordering]=&item_id=1&type_id=1&list[select]=(select 1 from (select
教程:www.cnblogs.com/jliangqiu2016/p/5597501.html 这里主要记载我编译遇到的错误及解决方法. OpenCV3.1软件下载:https://sourceforge.net/projects/opencvlibrary/ https://blog.csdn.net/liu798675179/article/details/51259505 Description 描述 The Open Source Computer Vision Library has
select floor(@f*0.22) -- 直接可显示结果 create table demo( id ,), id1 int ) select * from demo insert into demo(id1) union all union all union all union all --select top (FLOOR(@f*0.23)) * from dbo.demo /* 消息 1060,级别 15,状态 1,第 17 行 TOP 子句中的行数必须是整数. */ selec
一.Math类这三个方法的简介 1.round():取最接近的值. 对于这个方法,查看源代码,其实现如下: public static long round(double a) { if (a != 0x1.fffffffffffffp-2) // greatest double value less than 0.5 return (long)floor(a + 0.5d); else return 0; } 也就是将该值加0.5,然后取floor值. 2.floor():向下取整,或者说“向
最近开始打ctf了,发现好多sql注入都忘了,最近要好好复习一下. 基础知识: floor(): 去除小数部分 rand(): 产生随机数 rand(x): 每个x对应一个固定的值,但是如果连续执行多次值会变化,不过也是可预测的 floor报错payload: select count(), floor(rand(0)2) as a from information_schema.tables group by a; 原理: 这个payload的重点在group by a,也就是group by