.htaccess文件常见到[QSA][NC][L][R][F]几个字符在代码末尾,下边列出它们在静态规则中的作用,以备参考. NC : no case,不区分大小写,忽略大小写: L : last,表示已是最后一条规则,.htaccess文件解析将退出: R : redirect,重定向: F : forbidden,禁止访问. N : next(从头再来) NE : noescape (在输出中不对URI进行转义) NS : nosubreq (不对内部子请求进行处理) QSA :
完成R Programming第三周 这周作业有点绕,更多地是通过一个缓存逆矩阵的案例,向我们示范[词法作用域 Lexical Scopping]的功效.但是作业里给出的函数有点绕口,花费了我们蛮多心思. Lexical Scopping: The value of free variables are searched for in the environment where the function was defined. 因此 make.power<-function(n){ pow<
Dynamic len(set(a[L:R])) Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 https://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&page=show_problem&problem=3767 Description 给你n个数,m次操作 Q x y 询问[x+1,y]有多少个不同的数 M x y 将第x+1个数修改成y Input n
No Pain No Game Time Limit: 4000/2000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 2000 Accepted Submission(s): 851 Problem Description Life is a game,and you lose it,so you suicide. But you can not kill yours
给出一个有n个元素的数组,有以下两种操作:Q x y,求出区间[x,y)内不同元素的个数, M x y,把第x个元素的值修改为y.注意题目中的下标是从0开始的 这题超级超级坑 妈的一个水题找了几个小时的BUG 这样AC 这样WA 吃一堑长一智 妈的毒瘤啊 #include <bits/stdc++.h> using namespace std; typedef long long LL; ; int n, m, L, R, ans, sz, qsz, tsz; int a[max
Partial Sum Accepted : Submit : Time Limit : MS Memory Limit : KB Partial Sum Bobo has a integer sequence a1,a2,…,an of length n. Each time, he selects two ends ≤l<r≤n and add |∑rj=l+1aj|−C into a counter which is zero initially. He repeats the selec
D. Powerful array time limit per test seconds memory limit per test megabytes input standard input output standard output An array of positive integers a1, a2, ..., an ..., ar, ≤ l ≤ r ≤ n. For every positive integer s denote by Ks the number of occ
Problem G Time Limit : 2000/1000ms (Java/Other) Memory Limit : 131072/131072K (Java/Other) Total Submission(s) : 62 Accepted Submission(s) : 28 Font: Times New Roman | Verdana | Georgia Font Size: ← → Problem Description S number is the number wh