当使用mysql条件更新时--最先让人想到的写法 UPDATE buyer SET is_seller=1 WHERE uid IN (SELECT uid FROM seller) 此语句是错误的,会报错 You can't specify target table 'xxx' for update in FROM 这是因为: mysql的update的一些特点 1.update 时,更新的表不能在set和where中用于子查询: 2.update 时,可以对多个表进行更新(sqlserver
update tableA a,(select a.netbar_id,sum(a.reward_amt) reward_amt from tableB a group by a.netbar_id) b set a.transfer_amt=b.reward_amt where a.netbar_id=b.netbar_id; 执行该语句时要注意,因为 select a.netbar_id,sum(a.reward_amt) reward_amt from tableB a group by
mysql执行update报错 update library set status=true where 1=1 Error Code: 1175. You are using safe update mode and you tried to update a table without a WHERE that uses a KEY column To disable safe mode, toggle the option in Preferences -> SQL Queries and
mysql执行update报错 Err] 1055 - 'information_schema.PROFILING.SEQ' isn't in GROUP BY 今天开发的同事发来如下错误信息,最最简单的一个update操作,竟然报了[Err] 1055 - 'information_schema.PROFILING.SEQ' isn't in GROUP BY.具体sql语句为: [SQL]UPDATE draw_record SET open_price = '6945.98', buy_p
mysql for update语句 https://www.cnblogs.com/jtlgb/p/8359266.html For update带来的思考 http://www.cnblogs.com/Kidezyq/p/9239484.html?utm_source=debugrun&utm_medium=referral
UPDATE `WarningSendMail` AS alias_1 INNER JOIN (SELECT * FROM `WarningSendMail` WHERE flag=1 AND topic_id LIKE "%2267%") AS alias_2 SET alias_1.topic_id = REPLACE(alias_1.topic_id,'|2267','') WHERE alias_1.id = alias_2.id update WarningSendMail