LeetCode Meeting Rooms

原题链接在这里：https://leetcode.com/problems/meeting-rooms/

题目：

Given an array of meeting time intervals consisting of start and end times [[s1,e1],[s2,e2],...] (si < ei), determine if a person could attend all meetings.

For example,
Given [[0, 30],[5, 10],[15, 20]],
return false.

题解：

对array进行排序，从i = 1开始判断start是否在前一个end之前, 若是就return false. 完成loop返回true.

Time Complexity: O(nlogn). Space: O(1).

AC Java:

 /**

  * Definition for an interval.

  * public class Interval {

  *     int start;

  *     int end;

  *     Interval() { start = 0; end = 0; }

  *     Interval(int s, int e) { start = s; end = e; }

  * }

  */

 public class Solution {

     public boolean canAttendMeetings(Interval[] intervals) {

         if(intervals == null || intervals.length == 0){

             return true;

         }

         Arrays.sort(intervals, new Comparator<Interval>(){

             public int compare(Interval i1, Interval i2){

                 if(i1.start == i2.start){

                     return i1.end - i2.end;

                 }

                 return i1.start - i2.start;

             }

         });

         for(int i = 1; i<intervals.length; i++){

             if(intervals[i].start < intervals[i-1].end){

                 return false;

             }

         }

         return true;

     }

 }

跟上Meeting Rooms II

巴特西

LeetCode Meeting Rooms

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