HDU 5973 Game of Taking Stones 威佐夫博弈+大数
题目链接:
http://acm.hdu.edu.cn/showproblem.php?pid=5973
Game of Taking Stones
Time Limit: 2000/1000 MS (Java/Others)Memory Limit: 65536/65536 K (Java/Others)
#### 问题描述
> Two people face two piles of stones and make a game. They take turns to take stones. As game rules, there are two different methods of taking stones: One scheme is that you can take any number of stones in any one pile while the alternative is to take the same amount of stones at the same time in two piles. In the end, the first person taking all the stones is winner.Now,giving the initial number of two stones, can you win this game if you are the first to take stones and both sides have taken the best strategy?
输入
Input contains multiple sets of test data.Each test data occupies one line,containing two non-negative integers a andb,representing the number of two stones.a and b are not more than 10^100.
输出
For each test data,output answer on one line.1 means you are the winner,otherwise output 0.
样例输入
2 1
8 4
4 7
样例输出
0
1
0
题解
威佐夫博弈+大数
对于a,b(a<b),如果有floor((b-a)*((sqrt(5)+1)/2))==a,则为必败态。
import java.awt.peer.SystemTrayPeer;
import java.math.BigDecimal;
import java.text.DecimalFormat;
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
BigDecimal two=new BigDecimal(2);
BigDecimal thr=new BigDecimal(3);
BigDecimal fiv=new BigDecimal(5);
BigDecimal l=two,r=thr;
for(int i=0;i<500;i++){
BigDecimal mid=r.add(l).divide(two);
if(mid.multiply(mid).compareTo(fiv)<0){
l=mid;
}else{
r=mid;
}
}
BigDecimal gold=l.add(BigDecimal.ONE).divide(two);
BigDecimal a,b;
Scanner cin=new Scanner(System.in);
while(cin.hasNext()){
a=cin.nextBigDecimal();
b=cin.nextBigDecimal();
if(a.compareTo(b)>0){
BigDecimal tmp=a;
a=b;
b=tmp;
}
BigDecimal zero=a.subtract(b.subtract(a).multiply(gold).setScale(0,BigDecimal.ROUND_FLOOR));
//100位
BigDecimal sma=new BigDecimal("0.00000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000001");
if(zero.abs().compareTo(sma)<0){
System.out.println("0");
}else{
System.out.println("1");
}
}
}
}
最新文章
- @Autowired @Resource用法
- Excel Interactive View - 让页面表格的功能更强大
- 动画:UIKitAnimation 简单动画学习 iOS (一) 渐变 、 移动 、翻页、来回翻转 ——转载
- EditText的圆角与边框
- android 自定义折线图
- backup site collection
- 框架中web.xml中配置文件解析
- 安装 SQL Server 2005 的硬件和软件要求(官方全面)
- Web框架——Django笔记
- Run Loop简介
- android如何与asp.net服务端共享session
- Java-IO之PipedReader和PipedWriter
- mybatis笔记01
- SpringBoot mybatis配置
- Innodb ,MyISAM
- show processlist结果筛选
- gerrit管理下的git代码提交小技巧
- html5 canvas贝塞尔曲线篇(上)
- 如何移除EFI system partition?
- 如何使用Jquery 引入css文件