ACboy needs your help

Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 3282    Accepted Submission(s): 1703

Problem Description
ACboy has N courses this term, and he plans to spend at most M days on study.Of course,the profit he will gain from different course depending on the days he spend on it.How to arrange the M days for the N courses to maximize the profit?
 
Input
The input consists of multiple data sets. A data set starts with a line containing two positive integers N and M, N is the number of courses, M is the days ACboy has. Next follow a matrix A[i][j], (1<=i<=N<=100,1<=j<=M<=100).A[i][j] indicates if ACboy spend j days on ith course he will get profit of value A[i][j]. N = 0 and M = 0 ends the input.
 
Output
For each data set, your program should output a line which contains the number of the max profit ACboy will gain.
 
Sample Input
2 2
1 2
1 3
2 2
2 1
2 1
2 3
3 2 1
3 2 1
0 0
 
Sample Output
3
4
6
分组背包!....
 /*o1背包@龚细军*/
/*维度为2的01背包*/
#include<stdio.h>
#include<string.h>
#define maxn 102
int dp[maxn];
int aa[maxn][maxn]; int max(int a,int b)
{
return a>b?a:b;
}
int main()
{
int m,n,i,j,k;
while(scanf("%d%d",&n,&m),m+n)
{
memset(dp,,sizeof(dp));
for(i=;i<=n;i++) // class
for(j=;j<=m;j++) //day
scanf("%d",&aa[i][j]);
//对每一门课程进行背包施放
for(i=;i<=n;i++)
{
for(j=m;j>=;j--) //代表的是背包的容量
{
for(k=;k<=j;k++) //在这个容量内选择一个房间去,和之前放进去的比较!
dp[j]=max(dp[j],dp[j-k]+aa[i][k]);
}
}
printf("%d\n",dp[m]);
}
return ;
}

最新文章

  1. bzoj4305: 数列的GCD
  2. &#39;$.browser.msie&#39; 为空或不是对象
  3. javascript逻辑运算符“||”和“&amp;&amp;”
  4. Dictionary解析json,里面的数组放进list,并绑定到DataGridView指定列
  5. PAT-乙级-1044. 火星数字(20)
  6. 关于飞控下载时候出现avrdude: stk500_getsync(): not in sync: resp=0x00错误的解决方法
  7. [转]MySQL数据库的热备份
  8. Socket.io 延伸
  9. html 选择器之基础选择器
  10. Ubuntu source insight3稳定性
  11. [Google Codejam] Round 1A 2016 - The Last Word
  12. 关于Visio Studio 2012使用Nuget获取Sqlite驱动包报错:“System.Data.SQLite.EF6”的架构版本与 NuGet 的版本 2.0.30625.9003 不兼容
  13. JSP的三种注释方式
  14. 基于Windows环境下MyEclipse10快捷键总结
  15. jQuery概念
  16. 通过iis访问电脑文件
  17. inline-block和float 布局的选择
  18. javascript 闭包内部机制
  19. 1.23 codeforces div3 C.Nice Garland
  20. 网易云课堂Dubbo学习笔记

热门文章

  1. restful处理
  2. 玩转storm
  3. C语言编程规范
  4. 网站功能操作分布引导插件:Intro.js介绍;React里如何使用Intro.js以及如何进行分页导航
  5. 【ContestHunter】【弱省胡策】【Round5】
  6. @Java中使用Jedis操作Redis之一
  7. 第一章 mac下开发环境的配置
  8. Python的知识点 plt.plot()函数细节
  9. java 中的resultset的类型
  10. Android下 使用百度地图sdk