from collections import Counter

from operator import itemgetter

# txt_list可以写成函数参数进行导入

txt_list = ['千古','人间','人间','龙','龙','龙','哈哈哈','人才','千古','千古']

c = Counter()

for x in txt_list:

    if len(x) >= 1:

        if x == '\r\n' or x == '\n' or x == ' ':

            continue

        else:

            c[x] += 1

print('常用词频统计结果: \n')

for (k, v) in c.most_common(4): #打印排名前四位

    print('%s%s %s  %d' % ('  ' * (3 ), k, '*' * 3, v))

# 按照词频数从大到小打印

d = sorted(c.items(),key=itemgetter(1),reverse = True)

for ss,tt in d:

    out_words=ss + '\t' + str(tt)

    print(out_words)

#写入文件，多次写入，后一次覆盖前一次，但是out_words本身是在叠加的

#即：第一次写入的是：千古\t3\n;第二次写入的是：千古\t3\n龙\t3\n，覆盖上一次的数据;

#第三次是：千古\t3\n龙\t3\n人间\t2\n，继续覆盖上一次的数据

out_words = ''

for ss,tt in d:

    out_words=out_words + ss + '\t' + str(tt) + '\n'

    with open(r".\sss.txt", "w",encoding='utf-8') as f:

        f.write(out_words+'\n')

out_words = ''

for ss,tt in d:

    out_words=out_words + ss + '\t' + str(tt) + '\n'

with open(r".\ttt.txt", "w",encoding='utf-8') as f:

        f.write(out_words+'\n')