一、题目描述

A common divisor for two positive numbers is a number which both numbers are divisible by. It’s easy to calculate the greatest common divisor between tow numbers. But your teacher wants to give you a harder task, in this task you have to find the greatest common divisor d between two integers a and b that is in a given range from low to high (inclusive), i.e. low<=d<=high. It is possible that there is no common divisor in the given range.

二、输入

The first line contains an integer T (1<=T<=10)- indicating the number of test cases.

For each case, there are four integers a, b, low, high (1<=a,b<=1000,1<=low<=high<=1000) in one line.

三、输出

For each case, print the greatest common divisor between a and b in given range, if there is no common divisor in given range, you should print “No answer”(without quotes).

Sample Input

四、解题思路

题意：从low到high之间找出既能被a整除，又能被b整除的数，如果没有输出No answer

思路：这道题没什么好讲，就是遍历从high到low开始找一个既能被a整除又能被b整除就行了。

五、代码

#include<iostream>

using namespace std;

int main()

{

    int times;

    cin >> times;

    while(times--)

    {

        int a, b, low, high;

        cin >> a >> b >> low >> high;

        bool result;

        int divisor;

        for(divisor = high; divisor >= low; divisor--)

        {

            if(a % divisor == 0 && b % divisor == 0) {result = true; break;}

            result = false;

        }

        if(result) cout << divisor << endl;

        else cout << "No answer" << endl;

    }

    return 0;

}