Laravel find in set排序

做项目遇到个需求，需要对结果集中的数据进行指定规则的顺序排列。
例如，用户状态有四种：

0=>未激活；1=>正常；2=>禁用；3=>软删除

现在的需求是，我要按照：正常->未激活->禁用->删除；这个顺序来进行排序，同时按照注册时间降序，网上查了很多资料，国内提到这个的很少，在stackOverFlow上找到了答案！
先上解决方案：

public function index($customer_type = null) {

    $search = request('search');

    $perPage = request('perPage') ? request('perPage') : 10;

    $customer_type = $customer_type ? $customer_type : request('customer_type');

    // \DB::enableQueryLog();

    $data = Customer::select(['id', 'email', 'user_name', 'nick_name', 'status', 'phone', 'create_time'])

        ->where('customer_type', '=', $customer_type)

        ->where(function ($query) use ($search) {

            if ($search) {

                $query->where('user_name', 'like binary', '%' . $search . '%')

                    ->orWhere('nick_name', 'like binary', '%' . $search . '%')

                    ->orWhere('phone', 'like binary', '%' . $search . '%')

                    ->orWhere('email', 'like binary', '%' . $search . '%');

            }

        })

        ->orderByRaw("FIELD(status, " . implode(", ", [1, 2, 0, 3, 4]) . ")")

        ->orderBy('create_time', 'desc')

        ->paginate($perPage);

    // $query = \DB::getQueryLog();

    // dd($data);

    //追加额外参数，例如搜索条件

    $appendData = $data->appends(array(

        'search' => $search,

        'perPage' => $perPage,

    ));

    return view('admin/customer/customerList', compact('data'));

}

　　打印出来的sql语句如下：

参考了以下链接：
https://stackoverflow.com/questions/42068986/laravel-weird-behavior-orderbyrawfield

https://stackoverflow.com/questions/34244455/how-to-use-not-find-in-set-in-laravel-5-1

https://stackoverflow.com/questions/35594450/find-in-set-in-laravel-example/35594503

find_in_set 复杂应用：

public function get_teacher_list($timeType, $name, $perPage = 10, $personality = 0, $teachingStyle = 0, $ageType = 0)

{

    // \DB::enableQueryLog();

    $result_data = DB::table('teacher_info as ti')

        ->select('ti.*')

        ->join('customer', 'customer.id', '=', 'ti.customer_id')

        ->where(function ($query) use ($personality) {

            if (trim($personality)) {

                $query->whereRaw("find_in_set($personality,ti.label_ids)");

            }

        })

        ->where(function ($query) use ($teachingStyle) {

            if (trim($teachingStyle)) {

                $query->whereRaw("find_in_set($teachingStyle,ti.label_ids)");

            }

        })

        ->where(function ($query) use ($ageType) {

            if (trim($ageType)) {

                $ageType = explode('-', $ageType);

                $query->whereRaw("DATE_FORMAT(FROM_DAYS(TO_DAYS(NOW())-TO_DAYS(birthday)), '%Y')+0 between $ageType[0] and $ageType[1]");

            }

        })

        ->where(function ($query) use ($timeType) {

            //1本周，2下周

            if ($timeType == 1) {

                $query->where('ti.can_appointment_1', 1);

            } elseif ($timeType == 2) {

                $query->where('ti.can_appointment_2', 1);

            } else {

                $query->where('ti.can_appointment_1', '>', 0)

                    ->orWhere('ti.can_appointment_2', '>', 0);

            }

        })

        ->where(function ($query) use ($name) {

            if (trim($name)) {

                $query->where('ti.chinese_name', 'like', '%' . $name . '%')

                    ->orWhere('ti.english_name', 'like', '%' . $name . '%');

            }

        })

        ->where('ti.status', 1)

        ->orderBy('ti.total_teach_num', 'desc')

        ->orderBy('ti.total_star_num', 'desc')

        ->orderBy('ti.satisfaction', 'desc')

        ->orderBy('ti.comment_num', 'desc')

        ->orderBy('ti.english_name', 'asc')

        ->paginate($perPage);

    // dd($result_data, \DB::getQueryLog());

    return $result_data;

}

　　专门拿出来看一下:

$ids = array(1,17,2);

$ids_ordered = implode(',', $ids);

$items = User::whereIn('id', $ids)

 ->orderByRaw(DB::raw("FIELD(id, $ids_ordered)"))

 ->get();

　　转载：https://blog.csdn.net/zhezhebie/article/details/78357354

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Laravel find in set排序

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