Super Jumping! Jumping! Jumping!

Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)

Total Submission(s): 49436 Accepted Submission(s): 22871

Problem Description

Nowadays, a kind of chess game called “Super Jumping! Jumping! Jumping!” is very popular in HDU. Maybe you are a good boy, and know little about this game, so I introduce it to you now.

The game can be played by two or more than two players. It consists of a chessboard（棋盘）and some chessmen（棋子）, and all chessmen are marked by a positive integer or “start” or “end”. The player starts from start-point and must jumps into end-point finally. In the course of jumping, the player will visit the chessmen in the path, but everyone must jumps from one chessman to another absolutely bigger (you can assume start-point is a minimum and end-point is a maximum.). And all players cannot go backwards. One jumping can go from a chessman to next, also can go across many chessmen, and even you can straightly get to end-point from start-point. Of course you get zero point in this situation. A player is a winner if and only if he can get a bigger score according to his jumping solution. Note that your score comes from the sum of value on the chessmen in you jumping path.

Your task is to output the maximum value according to the given chessmen list.

Input

Input contains multiple test cases. Each test case is described in a line as follow:

N value_1 value_2 …value_N

It is guarantied that N is not more than 1000 and all value_i are in the range of 32-int.

A test case starting with 0 terminates the input and this test case is not to be processed.

Output

For each case, print the maximum according to rules, and one line one case.

Sample Input

Sample Output

题意

求上升子序列的和的最大值，注意对dp数组的初始化

AC代码

#include <stdio.h>

#include <string.h>

#include <iostream>

#include <algorithm>

#include <math.h>

#include <limits.h>

#include <map>

#include <stack>

#include <queue>

#include <vector>

#include <set>

#include <string>

#define ll long long

#define ms(a) memset(a,0,sizeof(a))

#define pi acos(-1.0)

#define INF 0x3f3f3f3f

const double E=exp(1);

const int maxn=1e6+10;

using namespace std;

int a[maxn];

int b[maxn];

int dp[maxn];

int main(int argc, char const *argv[])

{

	int n;

	while(~scanf("%d",&n)&&n)

	{

		ms(a);

		ms(dp);

		for(int i=0;i<n;i++)

		{

			cin>>a[i];

			// 对dp进行初始化

			dp[i]=a[i];

		}

		int ans=0;

		for(int i=0;i<n;i++)

		{

			for(int j=0;j<i;j++)

			{

				// 如果是递增的

				if(a[i]>a[j])

					// 加起来和原本的作比较

					dp[i]=max(dp[j]+a[i],dp[i]);

			}

			// 如果一开始不对dp初始化，要加上下面这一句

			// dp[i]=max(dp[i],a[i]);

			ans=max(ans,dp[i]);

		}

		cout<<ans<<endl;

	}

	return 0;

}

巴特西

HDU 1087：Super Jumping! Jumping! Jumping!（LIS）

Super Jumping! Jumping! Jumping!

题意

AC代码

最新文章

热门文章