html='''

<div>

    <ul>

        <li class="item-0">first item</li>

        <li class="item-1"><a href="link2.html">second item</a></li>

        <li class="item-0 active"><a href="link3.html"><span class="bold">third item</span></a></li>

        <li class="item-1 active"><a href="link4.html">fourth item</a></li>

        <li class="item-0 "><a href="link5.html">fifth item</a></li>

    </ul>

</div>

'''

from pyquery import PyQuery as pq

## 字符串初始化

doc = pq(html)

print(doc('li'))

## URL初始化

doc= pq(url='https://cuiqingcai.com')

print(doc('title'))

## 文件初始化

doc = pq(filename='test.html')

print(doc('li'))

# CSS选择器

from pyquery import PyQuery as pq

doc = pq(html)

## id用 #，class用 .

print(doc('#container .list li'))

html='''

<div id="container">

    <ul class="list">

        <li class="item-0">first item</li>

        <li class="item-1"><a href="link2.html">second item</a></li>

        <li class="item-0 active"><a href="link3.html"><span class="bold">third item</span></a></li>

        <li class="item-1 active"><a href="link4.html">fourth item</a></li>

        <li class="item-0 "><a href="link5.html">fifth item</a></li>

    </ul>

</div>

'''

##查找节点

from pyquery import PyQuery as pq

doc = pq(html)

items = doc('.list')

print(items)

## find() 查找所有地子孙节点

lis = items.find('a')

print(lis)

## children() 只查找子节点

lis = items.children('.active')

print(lis)

## parent() 查找父节点

container = items.parent()

print(container)

## parents() 查找祖先节点

ancestor = items.parents()

print(ancestor)

## siblings() 查找兄弟节点

li = doc('.item-0.active')

print(li.siblings('.active'))

from pyquery import PyQuery as pq

doc = pq(html)

## 调用items()得到一个生成器，for in 进行遍历

lis = doc('li').items()

for li in lis:

    print(li)

from pyquery import PyQuery as pq
doc = pq(html)
a = doc('.item-0 a')
print(a)

## 获取 a节点的 href的属性值
## attr()只返回第一个结果
print(a.attr('href'))
print(a.attr.href)

## 通过遍历获取所有的属性值
for item in a.items():
    print(item.attr('href'))

## 只获取文本 多个节点的文本内容用 空格 间隔开

print(a.text()) ## third item fifth item

## 获取包含 a节点内部所有内容，包含节点，返回第一个 a节点 内部的HTML文本

print(a.html()) # <span class="bold">third item</span>

## 节点操作

## remove()

html ='''

<div class="wrap">

    Hello World

    <p>呱呱呱</p>

</div>

'''

## 只想获得Hello World

from pyquery import  PyQuery as pq

doc = pq(html)

wrap = doc('.wrap')

## 移除 p节点

wrap.find('p').remove()

print(wrap.text())

html='''

<div id="container">

    <ul class="list">

        <li class="item-0">first item</li>

        <li class="item-1"><a href="link2.html">second item</a></li>

        <li class="item-0 active"><a href="link3.html"><span class="bold">third item</span></a></li>

        <li class="item-1 active"><a href="link4.html">fourth item</a></li>

        <li class="item-0 "><a href="link5.html">fifth item</a></li>

    </ul>

</div>

'''

from pyquery import PyQuery as pq

doc = pq(html)

## 第一个li节点

li = doc('li:first-child')

print(li)

## 最后一个li节点

li = doc('li:last-child')

print(li)

## 第2个li节点

li = doc('li:nth-child(2)')

print(li)

## 包含‘second’文本的li节点

li = doc('li:contains(second)')

print(li)