class Solution:

    def addBinary(self, a: str, b: str) -> str:

        list_a,list_b=[],[]

        for s in a:

            list_a.append(int(s))

        for s in b:

            list_b.append(int(s))

        if len(list_a)>=len(list_b):

            for i in range(len(list_a)-len(list_b)):

                list_b.insert(0,0)

        else:

            for i in range(len(list_b)-len(list_a)):

                list_a.insert(0,0)

        for i in range(len(list_b)):

            list_b[i]=list_b[i]+list_a[i]

        for i in range(len(list_b)-1,0,-1):

            if list_b[i]>1:

                list_b[i]=list_b[i]-2

                list_b[i-1]+=1

        if list_b[0]>1:

            list_b[0]=list_b[0]-2

            list_b.insert(0,1)

        for i in range(len(list_b)):

            list_b[i]=str(list_b[i])

        strb="".join(list_b)

        return strb

class Solution:

    def addBinary(self, a: str, b: str) -> str:

        return bin(int(a,2)+int(b,2))[2:]

class Solution:

    def addBinary(self, a: str, b: str) -> str:

        if len(a) < len(b):

            a,b = b,a

        b = ""*(len(a)-len(b)) + b

        carry = 0

        L = len(a)

        res = ''

        while L>0:

            tmp = int(a[L-1]) + int(b[L-1]) +carry

            carry = tmp // 2

            res += str(tmp % 2)

            L -= 1

        return (res + str(carry))[::-1] if carry else res[::-1]

dec = input('10进制数为：')

print("转换为二进制为：", bin(dec))

print("转换为八进制为：", oct(dec))

print("转换为十六进制为：", hex(dec))

string1 = ''

print('二进制字符串转换成十进制数为：'，int(string1,2))

string1 = ''

print('八进制字符串转换成十进制数为：'，int(string1,8))

string3 = 'FFF'

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作者：段小胖

来源：CSDN

原文：https://blog.csdn.net/dxcve/article/details/81153331