A1083 List Grades (25 分)

Given a list of N student records with name, ID and grade. You are supposed to sort the records with respect to the grade in non-increasing order, and output those student records of which the grades are in a given interval.

Input Specification:

Each input file contains one test case. Each case is given in the following format:

N

name[1] ID[1] grade[1]

name[2] ID[2] grade[2]

... ...

name[N] ID[N] grade[N]

grade1 grade2

where name[i] and ID[i] are strings of no more than 10 characters with no space, grade[i] is an integer in [0, 100], grade1 and grade2 are the boundaries of the grade's interval. It is guaranteed that all the grades are distinct.

Output Specification:

For each test case you should output the student records of which the grades are in the given interval [grade1, grade2] and are in non-increasing order. Each student record occupies a line with the student's name and ID, separated by one space. If there is no student's grade in that interval, output NONE instead.

Sample Input 1:

4

Tom CS000001 59

Joe Math990112 89

Mike CS991301 100

Mary EE990830 95

60 100

Sample Output 1:

Mike CS991301

Mary EE990830

Joe Math990112

Sample Input 2:

2

Jean AA980920 60

Ann CS01 80

90 95

Sample Output 2:

NONE

开始技术总结：

第一点就是初始化数组或是结构体的时候，大小要用常量，不能够使用输入量初始化
还有就是中文的括号注意一点
参考代码：

#define _CRT_SECURE_NO_WARNINGS

#include <cstdio>

#include <cstdlib>

#include <cstring>

#include <algorithm>

using namespace std;

const int MAXN = 50;

struct Student {

	char ID[11];

	char name[11];

	int grade;

}student[MAXN];

bool cmp(Student a, Student b) {

	if (a.grade != b.grade) return a.grade > b.grade;

}

int main(){

	int grade1, grade2;

	int N;

	scanf("%d", &N);

	for (int i = 0; i < N; i++) {

		scanf("%s%s%d", student[i].name, student[i].ID, &student[i].grade);

	}

	scanf("%d%d", &grade1, &grade2);

	sort(student, student + N, cmp);

	int flag = 0;//用来标记是否又符合条件的同学，0表示没有

	for (int j = 0; j < N; j++) {

		if (student[j].grade <= grade2 && student[j].grade >= grade1) {

			printf("%s %s\n", student[j].name, student[j].ID);

			flag = 1;

		}

	}

	if (flag == 0) {

		printf("NONE");

	}

	system("pause");

	return 0;

}

巴特西

A1083 List Grades (25 分)

开始技术总结：

最新文章

热门文章