#!/usr/bin/env python

#Python 3.7.0 元祖常用方法

__author__ = "lrtao2010"

#元祖和列表类似，只不过元祖一旦被创建一级元素不可更改（增删改）。

# a = ('123',['abc'],'b',345,['6','7','d'],)

# a[-1][2] = 'c'

# print(a)

# a[-1].append(123)

# print(a)

# ('123', ['abc'], 'b', 345, ['6', '7', 'c'])

# ('123', ['abc'], 'b', 345, ['6', '7', 'c', 123])

# a = ('123',['abc'],'b',345,['6','7','d'],)

# a[0] = '456'

# print(a)

#     a[0] = '456'

# TypeError: 'tuple' object does not support item assignment

#a = ('123','a',123，['a','b','c'],)

#元祖最后一个元素后面一般加上','号

# a = ('123',['abc'],'b',345,['6','7','d'],)

# v1 = a[1]

# v2 = a[2:]

# v3 = a[1:-1]

# print(v1)

# print(v2)

# print(v3)

# ['abc']

# ('b', 345, ['6', '7', 'd'])

# (['abc'], 'b', 345)

#可迭代

# a = ('123',['abc'],'b',345,['6','7','d'],)

# for i in a:

#     print(i)

#

#

# ['abc']

# b

#

# ['6', '7', 'd']

#count 统计指定值出现的次数

# a = ('a','b','a',['a','b','ab'],'ab',)

# v1 = a.count('a')

# v2 = a[3].count('b')

# print(v1,v2)

# 2 1

# index(self, *args, **kwargs)查找指定值的位置，不存在会报错

# a = ('a','b')

# v = a.index('b')

# print(v)

#