Problem 16

2024-10-01 06:03:06

Problem 16

pow(2, 15) = 32768 and the sum of its digits is 3 + 2 + 7 + 6 + 8 = 26.
2的15次方等于32768，而这些数字(3+2+7+6+8)的和为26
What is the sum of the digits of the number pow(2, 1000)?
2的1000次方的位数之和为多少？

import math

power = math.pow(2, 1000)

sum_of_digits = 0

with open('power_of_two.txt', 'w') as f:

    print('%d' % power, file=f)

with open('power_of_two.txt') as f:

    for line in f:

        for c in line:

            try:

                sum_of_digits += int(c)

            except:

                pass

print(sum_of_digits)

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