Maximun product
Given a sequence of integers S = {S1, S2, ..., Sn}, you shoulddetermine what is the value of the maximum positive product involving consecutive terms of S. Ifyou cannot find a positive sequence, you should consider 0 as the value of the maximum product.
Each test case starts with 1 ≤ N ≤ 18, the number of elements in a sequence. Each elementSi is an integer such that -10 ≤ Si ≤ 10. Next line will haveN integers, representing the value of each element in the sequence. There is a blank line aftereach test case. The input is terminated by end of file (EOF).
For each test case you must print the message: Case #M: The maximum product is P., where M isthe number of the test case, starting from 1, and P is the value of the maximum product. Aftereach test case you must print a blank line.
3
2 4 -3 5
2 5 -1 2 -1
Case #1: The maximum product is 8. Case #2: The maximum product is 20. 枚举每一个长度组合,不断更新最大值,不过要注意有可能18个数都是10,那么最大值是多少?int还存得下吗?
#include"iostream"
#include"cstring"
using namespace std;
int main()
{
long long ans=-;
int ch,f;
long long an=;
int a[];
f=;
int n;
while(cin>>n)
{
for(int i=;i<n;i++)
{
cin>>ch;
a[i]=ch;
an*=ch;
if(an>ans)
{
ans=an;
}
}
for(int j=n-;j>=;j--)
{
an=;
for(int k=j;k>=;k--)
{
an*=a[k];
if(an>ans)
{
ans=an;
}
}
}
if(ans<) ans=;
cout<<"Case #"<<f++<<": The maximum product is "<<ans<<'.'<<endl;
cout<<endl;
ans=-;
an=;
} return ;
}
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