A New Stone Game

Time Limit: 1000MS		Memory Limit: 30000K
Total Submissions: 5338		Accepted: 2926

Alice and Bob decide to play a new stone game.At the beginning of the game they pick n(1<=n<=10) piles of stones in a line. Alice and Bob move the stones in turn.
At each step of the game,the player choose a pile,remove at least
one stones,then freely move stones from this pile to any other pile that
still has stones.

For example:n=4 and the piles have (3,1,4,2) stones.If the player
chose the first pile and remove one.Then it can reach the follow states.

2 1 4 2

1 2 4 2（move one stone to Pile 2）

1 1 5 2（move one stone to Pile 3）

1 1 4 3（move one stone to Pile 4）

0 2 5 2（move one stone to Pile 2 and another one to Pile 3）

0 2 4 3（move one stone to Pile 2 and another one to Pile 4）

0 1 5 3（move one stone to Pile 3 and another one to Pile 4）

0 3 4 2（move two stones to Pile 2）

0 1 6 2（move two stones to Pile 3）

0 1 4 4（move two stones to Pile 4）

Alice always moves first. Suppose that both Alice and Bob do their best in the game.

You are to write a program to determine who will finally win the game.

The
input contains several test cases. The first line of each test case
contains an integer number n, denoting the number of piles. The
following n integers describe the number of stones in each pile at the
beginning of the game, you may assume the number of stones in each pile
will not exceed 100.

The last test case is followed by one zero.

For each test case, if Alice win the game,output 1,otherwise output 0.

3

2 1 3

2

1 1

0

1

0

 #include<cstdio>

 #include<algorithm>

 using namespace std;

 int n,a[];

 int main() {

     while(scanf("%d",&n)== && n) {

         for(int i=;i<=n;i++) scanf("%d",&a[i]);

         if(n&) puts("");

         else {

             sort(a+,a+n+);

             int flag=;

             for(int i=;i<=n;i+=)

                 if(a[i]!=a[i+]) { flag=; break; }

             if(flag) puts(""); else puts("");

         }

     }

     return ;

 }