Hints of sd0061

Time Limit: 5000/2500 MS (Java/Others) Memory Limit: 131072/131072 K (Java/Others)
Total Submission(s): 2421 Accepted Submission(s): 736

Problem Description

sd0061, the legend of Beihang University ACM-ICPC Team, retired last year leaving a group of noobs. Noobs have no idea how to deal with m coming contests. sd0061 has left a set of hints for them.

There are n noobs in the team, the i-th of which has a rating ai. sd0061 prepares one hint for each contest. The hint for the j-th contest is a number bj, which means that the noob with the (bj+1)-th lowest rating is ordained by sd0061 for the j-th contest.

The coach asks constroy to make a list of contestants. constroy looks into these hints and finds out: bi+bj≤bk is satisfied if bi≠bj, bi<bk and bj<bk.

Now, you are in charge of making the list for constroy.

Input

There are multiple test cases (about 10).

For each test case:

The first line contains five integers n,m,A,B,C. (1≤n≤107,1≤m≤100)

The second line contains m integers, the i-th of which is the number bi of the i-th hint. (0≤bi<n)

The n noobs' ratings are obtained by calling following function n times, the i-th result of which is ai.

unsigned x = A, y = B, z = C;
unsigned rng61() {
  unsigned t;
  x ^= x << 16;
  x ^= x >> 5;
  x ^= x << 1;
  t = x;
  x = y;
  y = z;
  z = t ^ x ^ y;
  return z;
}

Output

For each test case, output "Case #x: y1 y2 ⋯ ym" in one line (without quotes), where x indicates the case number starting from 1 and yi (1≤i≤m) denotes the rating of noob for the i-th contest of corresponding case.

Sample Input

3 3 1 1 1
0 1 2
2 2 2 2 2
1 1

Sample Output

Case #1: 1 1 202755
Case #2: 405510 405510

Source

2017 Multi-University Training Contest - Team 1

 #pragma comment(linker, "/STACK:102400000,102400000")

 #include <bits/stdc++.h>

 #include <cstdlib>

 #include <cstdio>

 #include <iostream>

 #include <cstdlib>

 #include <cstring>

 #include <algorithm>

 #include <cmath>

 #include <cctype>

 #include <map>

 #include <set>

 #include <queue>

 #include <bitset>

 #include <string>

 #include <complex>

 #define LL long long

 #define mod 1000000007

 using namespace std;

 int n,m;

 unsigned x,y,z,t,ans[];

 unsigned rng61(){

     x^=x<<;

     x^=x>>;

     x^=x<<;

     t=x;

     x=y;

     y=z;

     z=t^x^y;

     return z;

 }

 unsigned  aa[];

 struct node

 {

     int xx;

     int pos;

     friend bool operator < (node aaa,node bbb)

     {

         return aaa.xx < bbb.xx;

     }

 }bb[];

 int main()

 {

     int t=;

     while(scanf("%d %d %u %u %u",&n,&m,&x,&y,&z)!=EOF){

         for(int i=; i<=m; i++){

             scanf("%d",&bb[i].xx);

             bb[i].pos=i;

             }

         for(int i=; i<n; i++)

             aa[i]=rng61();

         sort(bb+,bb++m);

         bb[m+].xx=n;

         for(int i=m;i>=;i--){

             nth_element(aa,aa+bb[i].xx,aa+bb[i+].xx);

             ans[bb[i].pos]=aa[bb[i].xx];

         }

         printf("Case #%d:",++t);

         for(int i=;i<=m;i++)

             printf(" %u",ans[i]);

         printf("\n");

     }

     return ;

 }

巴特西

HDU 6040 stl

Hints of sd0061

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